QQuestionChemistry
QuestionChemistry
Draw the Lewis structure for the trisulfur molecule. Be sure to include all resonance structures that satisfy the octet rule.
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Answer
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Step 1:: Understand the problem and recall relevant information
The trisulfur molecule, S^3, consists of three sulfur atoms. To draw its Lewis structure, we need to follow these steps:
Step 2:
Determine the total number of valence electrons in the molecule.
Step 3:
Place the atoms in a reasonable arrangement.
Step 4:
Draw a trial structure with single bonds and distribute the remaining valence electrons as lone pairs.
Step 5:
Satisfy the octet rule by moving electrons between atoms (forming resonance structures if necessary).
Step 6:: Determine the total number of valence electrons
Sulfur is in the 16th group of the periodic table, so it has 6 valence electrons. For the S^3 molecule, there are a total of 3 x 6 = 18 valence electrons.
Step 7:: Place the atoms in a reasonable arrangement
A linear arrangement is the most stable for this molecule, with S-S-S bonding.
Step 8:: Draw a trial structure with single bonds and distribute the remaining valence electrons as lone pairs
Place one electron from each sulfur atom in each bond, using 2 electrons per bond. This uses up 6 x 2 = 12 electrons, leaving 18 - 12 = 6 electrons for lone pairs. Each sulfur atom gets one lone pair to satisfy the octet rule.
Step 9:: Satisfy the octet rule by moving electrons between atoms (forming resonance structures if necessary)
In this case, all atoms have an octet, so there are no resonance structures to draw.
Final Answer
The Lewis structure for the trisulfur molecule is: S-S-S || || :\ electron : \ : electron : \ : electron : || || S-S-S Each line represents a single bond, and each dot represents a lone pair of electrons. All sulfur atoms have an octet of electrons.
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