QQuestionChemistry
QuestionChemistry
Draw the Lewis structure of CH^3Br. Include lone pairs of electrons.
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Answer
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Step 1:I'll solve this Lewis structure problem step by step:
Step 2:: Determine the total number of valence electrons
Total valence electrons: $$4 + 3(1) + 7 = 14$$ electrons
- Carbon (C): 4 valence electrons - Hydrogen (H) × 3: 1 electron each (3 total) - Bromine (Br): 7 valence electrons
Step 3:: Arrange atoms in the structure
- Place carbon in the center - Attach three hydrogens to carbon - Attach bromine to the carbon
Step 4:: Connect atoms with single bonds
Electrons used in bonding: $$8$$ electrons
- Draw single bonds between: * Carbon and three hydrogens * Carbon and bromine
Step 5:: Distribute remaining electrons as lone pairs
- Remaining electrons: $$14 - 8 = 6$$ electrons
- Place 3 lone pairs on bromine - No additional lone pairs needed on carbon or hydrogens Final Lewis Structure: - Carbon at center - Three hydrogens single-bonded to carbon - Bromine single-bonded to carbon - Three lone pairs on bromine
Final Answer
[A Lewis structure showing carbon in the center, three hydrogen atoms single-bonded to carbon, bromine single-bonded to carbon, with three lone pairs on bromine]
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