QQuestionChemistry
QuestionChemistry
Draw the Lewis structure of NCO − (with minimized formal charges) and then choose the appropriate formal charges for each of the atoms.
A. N= 0,C= 0,O=−1
B. N=−1,C=+ 1,O=−1
C. N= 0,C= 0,O= 0
D. N=+ 1,C=−1,O=−1
E. N=−1,C= 0,O= 0
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Answer
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Step 1:I'll solve this step by step with precise LaTeX notation:
Step 2:: Determine the total number of valence electrons
Total valence electrons: $$5 + 4 + 6 + 1 = 16$$ electrons
• N: 5 valence electrons • C: 4 valence electrons • O: 6 valence electrons • Negative charge adds 1 electron
Step 3:: Arrange atoms in skeleton structure
• Place N, C, O in order: N-C-O • Connect with single bonds, using 6 electrons
Step 4:: Distribute remaining electrons
• Remaining electrons: $$16 - 6 = 10$$ electrons
• Complete octets by adding lone pairs to atoms
Step 5:: Draw Lewis structure
• Double bond between C and O • Lone pairs on N and O • Negative charge on O
Step 6:: Calculate formal charges
• O: $$6 - 4 - \frac{1}{2}(4) = -1
Final Answer
The correct answer is A: N= 0, C= 0, O=−1.
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