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QuestionChemistry

Draw the Lewis structure(2$) for the molecule with the chemical formula C^2H^3N, where the N is connected to only one other atom. How many double bonds are there in the correct Lewis structure?
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Answer

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Step 1:
I'll solve this step by step, following the LaTeX formatting guidelines precisely:

Step 2:
: Identify the atoms and their valence electrons

Total valence electrons: $$(2 \times 4) + (3 \times 1) + 5 = 16$$ electrons
- Carbon (C): 4 valence electrons - Hydrogen (H): 1 valence electron - Nitrogen (N): 5 valence electrons

Step 3:
: Determine the connectivity

- The problem states N is connected to only one other atom - This suggests a structure where N is at the end of the molecule

Step 4:
: Arrange atoms in a possible structure

- Likely structure: H-C-C≡N - This is called acetonitrile (or methyl cyanide)

Step 5:
: Draw the Lewis structure

- Single bonds between H-C and C-C - Triple bond between C and N - Distribute remaining electrons as lone pairs

Step 6:
: Count double bonds

- There are NO double bonds in this structure - There is ONE triple bond between C and N

Final Answer

The Lewis structure has 0 double bonds, but 1 triple bond in the C≡N group.