QQuestionChemistry
QuestionChemistry
# Draw the product of this reaction. Ignore inorganic byproducts. H₂C=O H HO-H H H OH OH OH CH₃OH NaBH₄, CH₃OH Drawing Q
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Step 1:I'll solve this organic chemistry reaction problem step by step:
Step 2:: Identify the Starting Materials
- The reactant is formaldehyde (H₂C=O) - The reducing agent is sodium borohydride (NaBH₄) in methanol (CH₃OH)
Step 3:: Understand the Reaction Mechanism
- NaBH₄ is a strong reducing agent that converts aldehydes to alcohols - The reaction will reduce the C=O (carbonyl) group to a CH₂OH (alcohol) group
Step 4:: Draw the Product
- The carbon will remain unchanged - The oxygen will be converted to a hydroxyl (OH) group - The final product will be methanol (CH₃OH)
Step 5:: Verify the Transformation
\text{H}_2\text{C=O} + \text{NaBH}_4 \rightarrow \text{H}_2\text{C(OH)}_2
Final Answer
The product of the reaction is methanol (CH₃OH), which is a simple alcohol derived from formaldehyde through reduction with sodium borohydride. [Note: The structure would be drawn with the methanol molecular structure showing the CH₃OH configuration]
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