QQuestionChemistry
QuestionChemistry
Fill in the name and empirical formula of each ionic compound that could be formed from the ions mg^2 +s^2 -,mg^2 +n^3 -,mg^2 +p^3 -,mg^2 + 02 -
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Answer
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Step 1:
For the ionic compound formed between Mg²+ and S²-, the empirical formula is MgS. This is because magnesium always loses two electrons to form an Mg²+ ion, and sulfur always gains two electrons to form an S²- ion. Therefore, one magnesium ion will combine with one sulfur ion to form an electrically neutral compound.
Step 2:: Write the charges of the ions
Mg^{2+} \text{ and } S^{2-}
Step 3:: Find the number of ions needed to balance the charges
2 \times (Mg^{2+}) = 2^+
1 \times (S^{2 -}) = 2^- Since the charges are balanced, one Mg²+ ion will combine with one S²- ion.
Step 4:: Write the empirical formula
MgS
Step 5:
For the ionic compound formed between Mg²+ and N³-, the empirical formula is Mg₃N₂. This is because magnesium always loses two electrons to form an Mg²+ ion, and nitrogen always gains three electrons to form an N³- ion. Therefore, three magnesium ions will combine with two nitrogen ions to form an electrically neutral compound.
Step 6:: Write the charges of the ions
Mg^{2+} \text{ and } N^{3-}
Step 7:: Find the number of ions needed to balance the charges
3 \times (Mg^{2+}) = 6^+
2 \times (N^{3 -}) = 6^- Since the charges are balanced, three Mg²+ ions will combine with two N³- ions.
Step 8:: Write the empirical formula
Mg_3N_2
Step 9:
For the ionic compound formed between Mg²+ and P³-, the empirical formula is Mg₃P₂. This is because magnesium always loses two electrons to form an Mg²+ ion, and phosphorus always gains three electrons to form an P³- ion. Therefore, three magnesium ions will combine with two phosphorus ions to form an electrically neutral compound.
Step 10:: Write the charges of the ions
Mg^{2+} \text{ and } P^{3-}
Step 11:: Find the number of ions needed to balance the charges
3 \times (Mg^{2+}) = 6^+
2 \times (P^{3 -}) = 6^- Since the charges are balanced, three Mg²+ ions will combine with two P³- ions.
Step 12:: Write the empirical formula
Mg_3P_2
Step 13:
For the ionic compound formed between Mg²+ and O²-, the empirical formula is MgO. This is because magnesium always loses two electrons to form an Mg²+ ion, and oxygen always gains two electrons to form an O²- ion. Therefore, one magnesium ion will combine with one oxygen ion to form an electrically neutral compound.
Step 14:: Write the charges of the ions
Mg^{2+} \text{ and } O^{2-}
Step 15:: Find the number of ions needed to balance the charges
1 \times (Mg^{2+}) = 2^+
1 \times (O^{2 -}) = 2^- Since the charges are balanced, one Mg²+ ion will combine with one O²- ion.
Step 16:: Write the empirical formula
MgO
Final Answer
The names and empirical formulas of the ionic compounds are: 1. MgS 2. Mg₃N₂ 3. Mg₃P₂ 4. MgO
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