QQuestionChemistry
QuestionChemistry
Find the subshell from which an electron was removed to form + 1 cation and the subshell to which an electron was added to form - 1 anion. H Cs Cd Kr
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Answer
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Step 1:: Identify the elements and their electron configurations.
- Hydrogen (H): 1s¹ - Caesium (Cs): [Xe] 6s¹ - Cadmium (Cd): [Kr] 5s² 4d¹⁰ - Krypton (Kr): [Ar] 4s² 3d¹⁰ 4p⁶
Step 2:: Determine the subshell from which an electron was removed to form a cation.
- For H, there is no change in the subshell since it loses one electron to become a + 1 cation (H⁺). - For Cs, an electron is removed from the 6s subshell to form a + 1 cation (Cs⁺). - For Cd, an electron is removed from the 5s subshell to form a + 1 cation (Cd⁺). - For Kr, there is no change in the subshell since it does not form a + 1 cation naturally.
Step 3:: Determine the subshell to which an electron was added to form an anion.
- For H, an electron is added to the 1s subshell to form a - 1 anion (H⁻). - For Cs, an electron is added to the 6p subshell to form a - 1 anion (Cs⁻). - For Cd, an electron is added to the 5p subshell to form a - 1 anion (Cd⁻). - For Kr, an electron is added to the 4d subshell to form a - 1 anion (Kr⁻).
Final Answer
- The subshell from which an electron was removed to form a + 1 cation is: 1s for H, 6s for Cs, 5s for Cd, and no change for Kr. - The subshell to which an electron was added to form a - 1 anion is: 1s for H, 6p for Cs, 5p for Cd, and 4d for Kr.
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