QQuestionChemistry
QuestionChemistry
For each atom find the subshell from which electron removed to form + 1 cation, and the subshell to which electron added to form
−1 anion
H
I
Kr
Be
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Answer
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Step 1:
H^{-}: 1s^{2}
When forming a + 1 cation, one electron is removed. This happens from the 1s subshell: For forming a - 1 anion, an electron is added to the neutral atom. This electron will occupy the 1s subshell:
Step 2:
I^{-}: [Kr] 5s^2 4d^{10} 5p^6
When forming a + 1 cation, one electron is removed. This happens from the 5p subshell: For forming a - 1 anion, an electron is added to the neutral atom. This electron will occupy the 5p subshell:
Step 3:
Be^{-}: 1s^2 2s^3
When forming a + 1 cation, one electron is removed. This happens from the 2s subshell: For forming a - 1 anion, an electron is added to the neutral atom. This electron will occupy the 2s subshell:
Step 4:
Kr^{-}: [Ar] 4s^2 3d^{10} 4p^7
Since krypton is a noble gas, it does not form ions easily. However, if we were to remove an electron to form a + 1 cation, it would come from the 4p subshell: Adding an electron to form a - 1 anion, the electron would occupy the 4p subshell: **
Final Answer
- Hydrogen: - + 1 cation: 1s^0 - - 1 anion: 1s^2 - Iodine: - + 1 cation: [Kr] 5s^2 4d^{10} 5p^4 - - 1 anion: [Kr] 5s^2 4d^{10} 5p^6 - Beryllium: - + 1 cation: 1s^2 2s^1 - - 1 anion: 1s^2 2s^3 - Krypton: - + 1 cation: [Ar] 4s^2 3d^{10} 4p^5 - - 1 anion: [Ar] 4s^2 3d^{10} 4p^7
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