QQuestionChemistry
QuestionChemistry
"Give the molecular geometry and number of electron groups for XeF^2.
A. Seesaw, 5 electron groups
B. T-shaped, 5 electron groups
C. Linear, 5 electron groups
D. Square planar, 6 electron groups
E. Octahedral, 6 electron groups"
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Answer
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Step 1:Let's solve this step by step using VSEPR (Valence Shell Electron Pair Repulsion) theory:
Step 2:: Determine the number of valence electrons for Xe
- Total valence electrons: $$8 + (2 \times 7) = 22$$ electrons
- Xenon (Xe) is in Group 18 - Xe has 8 valence electrons - Each F contributes 7 valence electrons
Step 3:: Draw the Lewis structure
- Central Xe atom - Two F atoms bonded to Xe - Remaining electrons form lone pairs on Xe
Step 4:: Count electron groups around the central atom
- Total: $$5$$ electron groups
- 2 bonding groups (Xe-F bonds) - 3 lone pairs on Xe
Step 5:: Determine electron group geometry
- 5 electron groups follow trigonal bipyramidal electron geometry - Lone pairs preferentially occupy equatorial positions
Step 6:: Determine molecular geometry
- Molecular geometry is $$\textbf{linear}
- With 2 bonding groups and 3 lone pairs
Final Answer
Linear, 5 electron groups
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