QQuestionChemistry
QuestionChemistry
How can millimoles (mmol) be calculated from molarity and volume? Given that molarity is defined as mol/L, why can molarity also be calculated from mmol/mL?
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Answer
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Step 1:I'll solve this problem step by step, following the specified LaTeX formatting guidelines:
Step 2:: Understanding the Basic Relationship
\text{Molarity} = \frac{\text{moles of solute}}{\text{liters of solution}}
Molarity (M) is defined as the number of moles of solute per liter of solution:
Step 3:: Converting Between Units
1 \text{ mol} = 1000 \text{ mmol}
To convert between mmol and mol, we use the conversion:
Step 4:: Volume Conversion
1 \text{ L} = 1000 \text{ mL}
Similarly, for volume:
Step 5:: Demonstrating Equivalence
\frac{1 \text{ mmol}}{1 \text{ mL}} = \frac{(1 \times 10^{-3} \text{ mol})}{(1 \times 10^{-3} \text{ L})} = \frac{\text{mol}}{\text{L}}
The relationship between molarity in mol/L and mmol/mL is mathematically equivalent: This is because:
Step 6:: Calculation Example
- Equivalent in mmol/mL: $$0.5 \frac{\text{mmol}}{\text{mL}}
If you have a solution with 0.5 M concentration:
Final Answer
Millimoles (mmol) can be calculated from molarity and volume using the same mathematical relationship as mol/L. The units are directly convertible due to the 1000:1 conversion factor between mol and mmol, and L and mL. Therefore, molarity expressed as mol/L is numerically identical to concentration expressed as mmol/mL.
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