QQuestionChemistry
QuestionChemistry
# How many pairs of valence electrons do the bromine atoms have in the following molecules and ions?
1. BrF
2. $\mathrm{BrF}_{2}^{+}$
3. $\mathrm{BrF}_{6}^{+}$
4. $\mathrm{BrF}_{2}^{-}$
5. $\mathrm{BrF}_{5}^{-}$
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Answer
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Step 1:I'll solve this step by step, focusing on determining the number of valence electron pairs for bromine in each molecule/ion.
Step 2:: Understand Valence Electrons for Bromine
- Bromine is in Group 17 (VIIA) - Bromine has 7 valence electrons in its neutral state
Step 3:: Determine Valence Electrons in BrF
- Number of electron pairs: $$\frac{14}{2} = 7
- Bromine contributes 7 valence electrons - Fluorine contributes 7 valence electrons - Electron pairs around Br: 3 lone pairs, 1 bonding pair
Step 4:: Determine Valence Electrons in \mathrm{BrF}_{2}^{+}
- Number of electron pairs: $$\frac{20}{2} = 10
- Bromine contributes 7 valence electrons - Positive charge removes 1 electron - Electron pairs around Br: 3 lone pairs, 2 bonding pairs
Step 5:: Determine Valence Electrons in \mathrm{BrF}_{6}^{+}
- Number of electron pairs: $$\frac{48}{2} = 24
- Bromine contributes 7 valence electrons - Positive charge removes 1 electron - Electron pairs around Br: 3 lone pairs, 6 bonding pairs
Step 6:: Determine Valence Electrons in \mathrm{BrF}_{2}^{-}
- Number of electron pairs: $$\frac{22}{2} = 11
- Bromine contributes 7 valence electrons - Negative charge adds 1 electron - Electron pairs around Br: 3 lone pairs, 2 bonding pairs
Step 7:: Determine Valence Electrons in \mathrm{BrF}_{5}^{-}
- Number of electron pairs: $$\frac{43}{2} = 21.5$$ (rounds to 22)
- Bromine contributes 7 valence electrons - Negative charge adds 1 electron - Electron pairs around Br: 3 lone pairs, 5 bonding pairs
Final Answer
1. BrF: 7 electron pairs 2. \mathrm{BrF}_{2}^{+}: 10 electron pairs 3. \mathrm{BrF}_{6}^{+}: 24 electron pairs 4. \mathrm{BrF}_{2}^{-}: 11 electron pairs 5. \mathrm{BrF}_{5}^{-}: 22 electron pairs
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