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Step 1:I'll solve this step-by-step following the specified LaTeX formatting guidelines:
Step 2:: Determine the atomic number of Aluminum (Al)
- Aluminum's atomic number is 13 - This means a neutral Al atom has 13 protons and 13 electrons
Step 3:: Electron Configuration for Neutral Aluminum
- The electron configuration of Al is $$1s^{2} 2s^{2} 2p^{6} 3s^{2}
- Total electrons in a neutral Al atom: 13 electrons
Step 4:: Determine Valence Electrons in Neutral Aluminum
- Neutral Al has $$2$$ valence electrons
- Valence electrons are in the outermost shell
Step 5:: Calculate Valence Electrons in Al³⁺
- Since you cannot have negative valence electrons, Al³⁺ has $$0$$ valence electrons
- Al³⁺ means the atom has lost 3 electrons
Final Answer
Al³⁺ has 0 valence electrons.
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