QQuestionChemistry
QuestionChemistry
In the Lewis electron dot structure for O^2, how many additional dots (electrons) should be shown around each O atom?
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Answer
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Step 1:I'll solve this step-by-step following the specified LaTeX and formatting guidelines:
Step 2:: Determine the total number of valence electrons
\text{Total valence electrons} = 6 \times 2 = 12
- Oxygen (O) is in Group 16 (VIA) of the periodic table - Each oxygen atom has 6 valence electrons - For O₂, we need to calculate the total valence electrons
Step 3:: Understand the bonding requirements
\text{Electrons in double bond} = 4
- O₂ forms a double bond between the two oxygen atoms - A double bond uses 4 electrons (2 electrons per bond)
Step 4:: Calculate remaining electrons for dot structure
- Remaining electrons: $$12 - 4 = 8
- Total valence electrons: 12 - Electrons in double bond: 4
Step 5:: Distribute remaining electrons
\text{Additional electrons per O atom} = 4
- 8 remaining electrons will be distributed as lone pairs - Each oxygen atom will receive 4 additional electrons
Final Answer
4 additional dots (electrons) should be shown around each O atom in the Lewis electron dot structure of O₂.
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