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QuestionChemistry

Look at the Lewis structure of the following molecule and predict its 3 -D shape according to the VSEPR theory: Oxygen dichloride (OCl 2 ​ )
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Answer

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Step 1:
I'll solve this problem step by step using VSEPR theory and proper LaTeX notation:

Step 2:
: Determine the central atom and valence electrons

- Total valence electrons: $$6 + (2 \times 7) = 20$$ electrons
- The central atom is oxygen (O) - Oxygen has 6 valence electrons - Chlorine (Cl) has 7 valence electrons

Step 3:
: Draw the Lewis structure

- Arrange electrons to create a stable electron configuration - Oxygen is the central atom - Two chlorine atoms are bonded to oxygen - Typical Lewis structure shows single bonds and lone pairs

Step 4:
: Count electron domains around the central atom

- Total electron domains: $$4$$ domains
- Two single bonds to chlorine atoms - Two lone pairs on the oxygen atom

Step 5:
: Determine electron domain geometry

- $$AX_{2}E_{2}$$ type molecule (2 atoms, 2 lone pairs)
- With 4 electron domains, the electron domain geometry is tetrahedral

Step 6:
: Determine molecular geometry

- Expected bond angle less than $$109.5^\circ$$, approximately $$110^\circ
- Lone pairs cause slight distortion from ideal tetrahedral angle - Molecular shape is bent (V-shaped)

Final Answer

The 3 -D shape of oxygen dichloride (OCl₂) is bent (V-shaped) with a bond angle slightly less than tetrahedral.