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# Module 6 Test What is the molecular geometry of $\mathrm{BCl}_{3}$ $\bigcirc$ triginal planar $\bigcirc$ trigonal pyramid $\bigcirc$ tetrahedral $\bigcirc$ liner
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Step 1:
I'll solve this step by step using VSEPR theory to determine the molecular geometry of \mathrm{BCl}_{3}.

Step 2:
: Determine the central atom and number of valence electrons

- Central atom is Boron (B) - Boron has 3 valence electrons - Each Chlorine (Cl) contributes 7 valence electrons

Step 3:
: Draw the Lewis structure

- Total valence electrons: $$3 + (3 \times 7) = 24$$ electrons
- Boron forms single bonds with three chlorine atoms - Boron will have an incomplete octet (6 electrons)

Step 4:
: Count electron domains around the central atom

- 3 single bonds = 3 electron domains - No lone pairs on the central boron atom - Total electron domains: 3

Step 5:
: Determine electron domain geometry

- 3 electron domains arranged around the central atom - Electron domain geometry is trigonal planar

Step 6:
: Determine molecular geometry

- All electron domains are bonding domains - No lone pairs on the central atom - Molecular geometry matches electron domain geometry

Final Answer

The correct answer is trigonal planar, which matches the first option in the original multiple-choice question.