QQuestionChemistry
QuestionChemistry
### Part A
**Ag**
Express your answer as a signed integer.
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the oxidation state of Ag =
Subtotal: 1
### Part B
**Al³**
Express your answer as a signed integer.
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the oxidation state of Al³ =
Subtotal: 1
### Part C
**Na₂O**
Express your answer as signed integers separated by a comma.
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the oxidation states of Na₂O =
Subtotal: 1
### Part D
**H₂S**
Express your answer as signed integers separated by a comma.
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the oxidation states of H₂S =
Subtotal: 1
### Part E
**NO₃**
Express your answer as signed integers separated by a comma.
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the oxidation states of NO₃ =
Subtotal: 1
### Part F
**VO₄³**
Express your answer as signed integers separated by a comma.
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the oxidation states of VO₄³ =
Subtotal: 1
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Answer
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Step 1:I'm here to help you understand how to find the oxidation states for each of the given compounds.
Let's go through this step-by-step.
Step 2:**Ag**: Silver (Ag) is a transition metal, and its oxidation state is typically + 1.
So, the oxidation state of Ag is **+ 1 **.
Step 3:**Al³**: Aluminum (Al) usually has an oxidation state of + 3.
Therefore, the oxidation state of Al³ is **+ 3 **.
Step 4:**Na₂O**: Sodium (Na) usually has an oxidation state of + 1, and oxygen (O) has an oxidation state of - 2.
2*(+1) + (-2) = 0
In Na₂O, there are two sodium atoms and one oxygen atom. To balance the charge, we have: So, the oxidation states of Na₂O are **+ 1, + 1, - 2 **.
Step 5:**H₂S**: Hydrogen (H) typically has an oxidation state of + 1, and sulfur (S) has an oxidation state of - 2.
2*(+1) + (-2) = 0
In H₂S, there are two hydrogen atoms and one sulfur atom. To balance the charge, we have: So, the oxidation states of H₂S are **+ 1, + 1, - 2 **.
Step 6:**NO₃**: Nitrogen (N) usually has an oxidation state of - 3, but in this compound, it is in the + 5 state to balance the charge of the three oxygen atoms (O), each with an oxidation state of - 2.
(+5) + 3*(-2) = 0
In NO₃, there is one nitrogen atom and three oxygen atoms. To balance the charge, we have: So, the oxidation states of NO₃ are **+ 5, - 2, - 2, - 2 **.
Step 7:**VO₄³**: Vanadium (V) usually has various oxidation states, and in this compound, it is in the + 5 state to balance the charge of the four oxygen atoms (O), each with an oxidation state of - 2.
(+5) + 4*(-2) = 0
In VO₄³, there is one vanadium atom and four oxygen atoms. To balance the charge, we have: So, the oxidation states of VO₄³ are **+ 5, - 2, - 2, - 2, - 2 **. **
Final Answer
Part A: + 1 Part B: + 3 Part C: + 1, + 1, - 2 Part D: + 1, + 1, - 2 Part E: + 5, - 2, - 2, - 2 Part F: + 5, - 2, - 2, - 2, - 2
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