QQuestionChemistry
QuestionChemistry
Propane (C^3H8) has a molar mass of 44 g/mole. You started the day with a tank containing 9071 g of propane. At the end of the day, your tank contained 7532 g of propane gas. How many moles of gas did you use?
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Answer
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Step 1:Let's solve this problem step by step:
Step 2:: Identify the given information
- Molar mass of propane: $$44 \frac{\mathrm{g}}{\mathrm{mol}}
- Final mass of propane: 7532 \mathrm{~g}
Step 3:: Calculate the mass of propane used
9071 \mathrm{~g} - 7532 \mathrm{~g} = 1539 \mathrm{~g}
- Mass used = Initial mass - Final mass
Step 4:: Convert mass used to moles
\text{Moles} = \frac{\text{Mass used}}{\text{Molar mass}} = \frac{1539 \mathrm{~g}}{44 \frac{\mathrm{g}}{\mathrm{mol}}}
- Use the molar mass to convert from grams to moles
Step 5:: Calculate the number of moles
\text{Moles} = \frac{1539}{44} = 35.0 \mathrm{~mol}
Final Answer
35.0 \mathrm{~mol} of propane gas were used during the day.
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