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QuestionChemistry

Silver has an atomic number of 47. Give the number of protons, neutrons, and electrons in a neutral atom of the most common isotope, Ag- 107.
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Step 1:
: Determine the number of protons in a silver atom.

In any element, the atomic number is equal to the number of protons. For silver, the atomic number is 47, so there are 47 protons in a neutral silver atom. \boxed{\text{Number of protons} = 47}

Step 2:
: Identify the mass number of the most common isotope, Ag- 107.

The mass number is the sum of the number of protons and neutrons in the nucleus. For Ag- 107, the mass number is 107.

Step 3:
: Calculate the number of neutrons in the most common isotope.

To find the number of neutrons, subtract the number of protons from the mass number. For Ag- 107, the calculation is as follows: \text{Number of neutrons} = \text{Mass number} - \text{Number of protons} \text{Number of neutrons} = 107 - 47 \boxed{\text{Number of neutrons} = 60}

Step 4:
: Determine the number of electrons in a neutral silver atom.

In a neutral atom, the number of electrons is equal to the number of protons. Since there are 47 protons in a neutral silver atom, there are also 47 electrons. \boxed{\text{Number of electrons} = 47}

Final Answer

- Number of protons: 47 - Number of neutrons: 60 - Number of electrons: 47