QQuestionChemistry
QuestionChemistry
The formula for copper(II) sulfite is $\mathrm{CuSO}_{3}$.
a. How many grams of copper(II) sulfite are present in $2.12 \times 10^{22}$ formula units of this compound
$\square$ grams
b. How many formula units of copper(II) sulfite are present in 4.71 grams of this compound?
$\square$ formula units
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Answer
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Step 1:I'll solve this problem step by step using the specified LaTeX formatting guidelines.
Step 2:: Calculate the molar mass of copper(II) sulfite \mathrm{CuSO}_{3}
\begin{align}
- Atomic masses: - Molar mass calculation: \mathrm{Molar~Mass} &= 63.55 + 32.07 + (3 \times 16.00) \ &= 63.55 + 32.07 + 48.00 \ &= 143.62 \mathrm{~g/mol} \end{align}
Step 3:: Calculate grams of copper(II) sulfite in 2.12 \times 10^{22} formula units
\begin{align}
- Convert formula units to moles: &= 0.0352 \mathrm{~mol} \end{align} - Convert moles to grams: \text{Grams} &= 0.0352 \mathrm{~mol} \times 143.62 \mathrm{~g/mol} \ &= 5.05 \mathrm{~g} \end{align}
Step 4:: Calculate formula units in 4.71 grams of copper(II) sulfite
\begin{align}
- Convert grams to moles: &= 0.0328 \mathrm{~mol} \end{align} - Convert moles to formula units: \text{Formula Units} &= 0.0328 \mathrm{~mol} \times (6.022 \times 10^{23} \mathrm{~formula~units/mol}) \ &= 1.98 \times 10^{22} \mathrm{~formula~units} \end{align}
Final Answer
a. 5.05 \mathrm{~g} of copper(II) sulfite b. 1.98 \times 10^{22} \mathrm{~formula~units} of copper(II) sulfite
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