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QuestionChemistry

The hybridization state of the charged carbon in a carbocation is: A) sp^4 B) sp^3 C) sp^2 D) sp E) s
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Step 1:

The hybridization state of a carbon atom is determined by the number of atoms or groups of atoms bonded to it and the charge on the carbon. In a carbocation, there is a positive charge on the carbon, which means it has lost one electron and is now short one electron in its valence shell.

Step 2:

To achieve a stable electron configuration, the carbon will undergo hybridization to spread the positive charge over multiple bonds. In a carbocation, the carbon is bonded to three other atoms or groups of atoms, so it will undergo sp^2 hybridization.

Step 3:

In sp^2 hybridization, one s orbital and two p orbitals combine to form three sp^2 hybrid orbitals. These hybrid orbitals are arranged in a trigonal planar geometry, with bond angles of approximately 120 degrees. The remaining p orbital is not involved in hybridization and is perpendicular to the plane of the sp^2 hybrid orbitals.

Step 4:

The hybridization state of the charged carbon in a carbocation is therefore:

Final Answer

Explanation: The charged carbon in a carbocation undergoes sp^2 hybridization, resulting in a trigonal planar geometry with bond angles of approximately 120 degrees. This hybridization state allows the carbon to spread the positive charge over multiple bonds, making it more stable.