QQuestionChemistry
QuestionChemistry
The molecule XeF^2 does not obey the octet rule.
Draw its Lewis structure.
State the type of octet-rule exception.
Include lone pair electrons in the Lewis structure.
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Answer
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Step 1:I'll solve this problem step by step, following the specified LaTeX and formatting guidelines:
Step 2:: Determine the total number of valence electrons
- Total valence electrons: $$8 + 14 = 22$$ electrons
- Xe (Xenon): 8 valence electrons - F (Fluorine): 7 valence electrons × 2 = 14 valence electrons
Step 3:: Arrange atoms in the Lewis structure
\begin{array}{c}
- Place Xe in the center - Place two F atoms on opposite sides of Xe F-Xe-F \end{array}
Step 4:: Distribute electrons around atoms
- Remaining electrons: $$18 - 12 = 6$$ electrons
- Connect F atoms to Xe with single bonds (2 × 2 = 4 electrons) - Place 3 lone pairs on each F atom (6 electrons) - Place 3 lone pairs on central Xe atom
Step 5:: Final Lewis structure
\begin{array}{c}
F:\ddot{:} - Xe:\ddot{:} - F:\ddot{:} \end{array}
Step 6:: Identify octet rule exception
- Xe has more than 8 electrons (expanded octet) - This is an example of an expanded valence shell exception
Final Answer
- Lewis structure shows Xe with 12 electrons - Octet rule exception: Expanded valence shell - Central Xe atom has 3 lone pairs and 2 single bonds
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