QQuestionChemistry
QuestionChemistry
Use the periodic table to find the charge of the ion that each atom is most likely to form.
The charge of a sulfur (S) ion is
The charge of a potassium (K) ion is
The charge of a boron (B) ion is
The charge of an iodine (I) ion is
The charge of a bromine (Br) ion is
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Answer
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Step 1:I'll solve this systematically by examining the electron configuration and valence electrons for each element to determine their most likely ion charge.
Step 2:: Sulfur (S)
- Most likely ion charge: $$S^{2-}
- Atomic number: 16 - Valence electrons: 6 - To achieve noble gas configuration, sulfur tends to gain 2 electrons
Step 3:: Potassium (K)
- Most likely ion charge: $$K^{+}
- Atomic number: 19 - Valence electrons: 1 - To achieve noble gas configuration, potassium tends to lose 1 electron
Step 4:: Boron (B)
- Most likely ion charge: $$B^{3+}
- Atomic number: 5 - Valence electrons: 3 - To achieve noble gas configuration, boron tends to lose 3 electrons
Step 5:: Iodine (I)
- Most likely ion charge: $$I^{-}
- Atomic number: 53 - Valence electrons: 7 - To achieve noble gas configuration, iodine tends to gain 1 electron
Step 6:: Bromine (Br)
- Most likely ion charge: $$Br^{-}
- Atomic number: 35 - Valence electrons: 7 - To achieve noble gas configuration, bromine tends to gain 1 electron
Final Answer
- Sulfur (S): S^{2 -} - Potassium (K): K^{+} - Boron (B): B^{3 +} - Iodine (I): I^{-} - Bromine (Br): Br^{-}
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