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QuestionChemistry

Using the VSEPR theory, what is the shape of CH^2Cl^2? A. Bent: The chlorine atoms will push the hydrogen and carbon atoms farther away from them and closer to each other due to their greater electronegativity. B. Trigonal pyramidal: There are four shared pairs of electrons and no lone electron pairs in the molecule. C. Tetrahedral: There are four shared pairs of electrons and no lone electron pairs in the molecule. D. Linear: The atoms are all nonmetals with low electronegativity and will have equal repulsion forces on each other.
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Answer

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Step 1:
Let's solve this step by step using VSEPR (Valence Shell Electron Pair Repulsion) theory:

Step 2:
: Determine the central atom

- In CH₂Cl₂, carbon (C) is the central atom - Carbon has 4 valence electrons and forms 4 bonds

Step 3:
: Count the total number of electron domains

- 4 single bonds (C-H and C-Cl bonds) - No lone pairs on the central carbon atom - Total electron domains = 4

Step 4:
: Apply VSEPR theory rules

- With 4 electron domains and no lone pairs - The electron domains will arrange themselves to minimize repulsion - This results in a tetrahedral electron domain geometry

Step 5:
: Analyze molecular geometry

- Bond angles will be approximately $$109.5^\circ
- All 4 domains are bonding domains (no lone pairs) - This means the molecular shape is also tetrahedral

Step 6:
: Eliminate incorrect answers

- A (Bent): Incorrect - no lone pairs to cause bending - B (Trigonal pyramidal): Incorrect - requires a lone pair - D (Linear): Incorrect - does not match the electron domain arrangement

Final Answer

Tetrahedral The key is recognizing that the 4 electron domains around carbon arrange in a tetrahedral geometry with no lone pairs, resulting in a tetrahedral molecular shape.