QQuestionChemistry
QuestionChemistry
"What are the angles between the bonds of the molecule Xenon difluoride (XeF2)?"
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Answer
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Step 1:I'll solve this problem step by step, focusing on molecular geometry and VSEPR theory.
Step 2:: Determine the central atom and valence electrons
- The central atom is Xenon (Xe) - Fluorine atoms (F) are terminal atoms - Xe has 8 valence electrons - Each F contributes 7 valence electrons
Step 3:: Calculate total valence electrons
8 + (2 \times 7) = 22 \text{ valence electrons}
Step 4:: Draw Lewis structure
- Xe forms two single bonds with F atoms - Remaining electrons form lone pairs on Xe
Step 5:: Apply VSEPR Theory
- Xe has 3 electron domains (2 bonding, 1 lone pair) - Electron domain geometry: Trigonal planar - Molecular geometry: Linear
Step 6:: Determine bond angles
- In a linear molecular geometry, the bond angle is $$180^\circ
- The two F atoms are positioned on opposite sides of the Xe atom
Final Answer
The angle between the Xe-F bonds in XeF₂ is 180^\circ.
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