QQuestionChemistry
QuestionChemistry
What are the expected bond angles in ICl 4 +?
Select all that apply:
A. 90 degrees
B. 109.5 degrees
C. 180 degrees
D. 120 degrees
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Answer
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Step 1:Let's solve this step by step using VSEPR (Valence Shell Electron Pair Repulsion) theory:
Step 2:: Determine the central atom and its electron configuration
- The central atom is I (Iodine) - In ICl₄⁺, iodine is the central atom - We need to count the electron domains around the central atom
Step 3:: Calculate the electron domains
- Total electron domains: $$\frac{7 + 28 - 1}{2} = 17
- Iodine's valence electrons: 7 - Chlorine atoms: 4 × 7 = 28 - Positive charge removes 1 electron
Step 4:: Determine molecular geometry
- Total electron domains: 5 - Electron domain geometry: Trigonal bipyramidal - Actual molecular geometry: Square planar
Step 5:: Analyze bond angles
- In a square planar geometry, the bond angles are: * Between adjacent chlorine atoms: 90 degrees * Between opposite chlorine atoms: 180 degrees
Step 6:: Identify possible bond angles
Final Answer
The bond angles in ICl₄⁺ are 90 degrees and 180 degrees. Explanation: The square planar geometry results from the specific electron domain arrangement that minimizes electron pair repulsion.
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