QQuestionChemistry
QuestionChemistry
What is the approximate chlorine-carbon-chlorine bond angle in C^2Cl^4?
12 months agoReport content
Answer
Full Solution Locked
Sign in to view the complete step-by-step solution and unlock all study resources.
Step 1:
The molecule CCl$_4$ is tetrahedral with a bond angle of 109.5 degrees.
However, when a molecule like C$_1$Cl$_1$ is not symmetrical, it deviates from the idealized bond angles.
Step 2:
In C$_2$Cl$_4$, there are two types of bond angles: the chlorine-carbon-chlorine (Cl-C-Cl) bond angle and the chlorine-carbon-chlorine (Cl-C-Cl) bond angle involving the two carbon atoms.
Step 3:
The Cl-C-Cl bond angle is affected by the presence of the other carbon atom. This results in a smaller bond angle compared to the ideal tetrahedral angle.
Step 4:
The difference in bond angle is due to the repulsion between the electron pairs around the central carbon atom. In this case, the repulsion between the two bonding pairs of electrons (Cl-C) is less than the repulsion between a bonding pair and a lone pair of electrons.
Step 5:
where $\Delta$ is the difference in electron pair repulsion between the two types of electron pairs involved in the bond angle.
The bond angle can be calculated using the formula:
Step 6:
In C$_2$Cl$_4$, the central carbon atom has two bonding pairs of electrons and two lone pairs of electrons.
The repulsion between a bonding pair and a lone pair of electrons is greater than the repulsion between two bonding pairs of electrons.
Step 7:
\Delta \approx \text{repulsion between bonding pair and lone pair} - \text{repulsion between two bonding pairs}
Step 8:
Therefore, $\Delta$ is positive.
The repulsion between a bonding pair and a lone pair of electrons is greater than the repulsion between two bonding pairs of electrons.
Step 9:
The exact value of $\Delta$ depends on the specific molecule and can be determined experimentally or through quantum chemical calculations.
However, for the purpose of this problem, we can estimate $\Delta$ to be around 10 - 15 degrees.
Step 10:
\angle Cl-C-Cl \approx 109.5^\circ - \frac{1}{2} \times 10^\circ = 104.5^\circ
Substituting this value into the formula for the Cl-C-Cl bond angle, we get:
Final Answer
The approximate chlorine-carbon-chlorine bond angle in C$_1$Cl$_1$ is 104.5 degrees.
Need Help with Homework?
Stuck on a difficult problem? We've got you covered:
- Post your question or upload an image
- Get instant step-by-step solutions
- Learn from our AI and community of students