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QuestionChemistry

What is the bond order of Li^2− ? Express the bond order numerically.
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Step 1:
: Write out the electron configuration for a Li atom.

Its electron configuration is $$1s^2 2s^1$$.
A neutral lithium atom has 3 electrons.

Step 2:
: Determine the electron configuration for the Li^2− ion.

The electron configuration for each lithium atom in the Li2− ion is then $$1s^1 2s^2$$.
The Li^2− ion has two lithium atoms that have donated one electron each to form a bond, resulting in a total of 4 electrons being shared between the two atoms. To accommodate these 4 electrons, one of the lithium atoms is promoted from its ground state to an excited state.

Step 3:
: Calculate the bond order.

The bond order is given by the formula: In the Li^2− ion, there are 2 electrons in the bonding molecular orbital and none in the antibonding molecular orbital. Therefore, the bond order is:

Final Answer

The bond order of Li^2− is 1, indicating a single bond between the two lithium atoms.