QQuestionChemistry
QuestionChemistry
What is the correct Lewis structure for N^2?
A. N-N
B. :-:
C. =
D. : N ≡ N :
E. none of the above
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Answer
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Step 1:I'll solve this step by step with precise LaTeX formatting:
Step 2:: Analyze the Nitrogen Molecule
- Nitrogen (N) is in Group 5A (15) on the periodic table - Each nitrogen atom has 5 valence electrons - In a diatomic nitrogen molecule, two nitrogen atoms will combine
Step 3:: Electron Configuration
- Total valence electrons: $$5 \times 2 = 10$$ electrons
- These electrons must be arranged to create a stable bond
Step 4:: Bonding Analysis
- To achieve a stable octet, nitrogen atoms will form a triple bond - This means 6 electrons will be shared in the bond - The remaining 4 electrons will be lone pair electrons
Step 5:: Lewis Structure Representation
- Lone pair electrons ($$:$$) on each nitrogen atom
- Triple bond (\equiv) between nitrogen atoms
Step 6:: Verify Electron Arrangement
- 6 bonding electrons in triple bond - 4 non-bonding (lone pair) electrons - Each nitrogen atom has a complete octet
Final Answer
D. : N \equiv N : is the correct Lewis structure for N₂.
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