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QuestionChemistry

What is the electron configuration of a nitride ion N 3− ?
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Step 1:
I'll solve this step-by-step, following the LaTeX formatting guidelines precisely:

Step 2:
: Determine the atomic number of nitrogen

- Its neutral atomic configuration is $$1s^{2} 2s^{2} 2p^{3}
- Nitrogen is element 7 on the periodic table

Step 3:
: Calculate the number of electrons for a nitride ion

- Nitride ion has a 3− charge - This means it gains 3 additional electrons - Neutral nitrogen has 7 electrons - Nitride ion will have 7 + 3 = 10 electrons total

Step 4:
: Write the electron configuration for N³⁻

- $$1s^{2} 2s^{2} 2p^{6}
- Fill orbitals systematically from lowest to highest energy

Step 5:
: Verify the configuration

- $$2p^{6}$$ (6 more electrons)
- 2s^{2} (2 more electrons) - Total: 10 electrons - Matches the expected configuration for N³⁻

Final Answer

The electron configuration of a nitride ion N³⁻ is 1s^{2} 2s^{2} 2p^{6}.