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What is the electron group geometry and molecular geometry, respectively, for the molecule XeF^2? A. trigonal bipyramidal, linear B. trigonal bipyramidal, bent C. tetrahedral, bent D. octahedral, bent E. octahedral, linear
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Answer

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Step 1:
Let's solve this step by step using VSEPR (Valence Shell Electron Pair Repulsion) theory:

Step 2:
: Determine the number of valence electrons

- Total valence electrons: $$8 + 14 = 22$$ electrons
- Xe (Xenon): 8 valence electrons - F (Fluorine): 7 valence electrons × 2 = 14 valence electrons

Step 3:
: Draw the Lewis structure

- Xe will be the central atom - Place 2 single bonds to F atoms - Remaining electrons will be lone pairs on Xe - Total electron domains around Xe: 5 (2 bonding, 3 lone pairs)

Step 4:
: Electron Group Geometry

\text{Electron domains} = 5
- 5 total electron domains - Electron group geometry is trigonal bipyramidal

Step 5:
: Molecular Geometry

- 2 bonding domains - 3 lone pair domains - Lone pairs occupy equatorial positions to minimize repulsion - Resulting molecular geometry is linear

Final Answer

Explanation: The key is recognizing that while the electron group geometry is trigonal bipyramidal with 5 total domains, the actual molecular geometry is linear due to the specific arrangement of the lone pairs.