QQuestionChemistry
QuestionChemistry
What is the equation for the base dissociation constant, $K_{b}$, of $\mathrm{NH}_{3}$ ?
\mathrm{NH}_{3}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(1) \rightleftharpoons \mathrm{NH}_{4}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})
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Answer
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Step 1:I'll solve this step by step, following the precise LaTeX formatting guidelines:
Step 2:: Understand the Base Dissociation Reaction
The reaction shows ammonia ($\mathrm{NH}_{3}$) reacting with water to produce ammonium ions ($\mathrm{NH}_{4}^{+}$) and hydroxide ions ($\mathrm{OH}^{-}$).
Step 3:: Recall the Base Dissociation Constant ($K_{b}$) Definition
The base dissociation constant is defined as the equilibrium concentration of products divided by the concentration of reactants.
Step 4:: Write the $K_{b}$ Equation
K_{b} = \frac{[\mathrm{NH}_{4}^{+}][\mathrm{OH}^{-}]}{[\mathrm{NH}_{3}]}
Step 5:: Explain the Equation Components
- $[\mathrm{NH}_{3}]$ is the concentration of ammonia
- $[\mathrm{OH}^{-}]$ is the concentration of hydroxide ions
Final Answer
K_{b} = \frac{[\mathrm{NH}_{4}^{+}][\mathrm{OH}^{-}]}{[\mathrm{NH}_{3}]}
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