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Step 1:I'll solve this step by step, focusing on determining the hybridization of carbon atoms in tetrachloroethene (C^2Cl4).
Step 2:: Analyze the molecular structure
- C^2Cl^4 is a planar molecule with a double bond between the two carbon atoms - Each carbon atom is bonded to two chlorine atoms and the adjacent carbon atom
Step 3:: Determine the number of electron domains around each carbon
- Total electron domains per carbon = $$2 + 2 = 4
- Double bond between carbons counts as 2 electron domains - Single bonds to chlorine atoms count as 1 electron domain each
Step 4:: Relate electron domains to hybridization
- 4 electron domains corresponds to sp^{2} hybridization - This means: * 3 hybrid orbitals in the same plane * 1 unhybridized p orbital perpendicular to the plane
Step 5:: Confirm bonding characteristics
* Two sigma ($$\sigma$$) bonds with chlorine atoms
- sp^{2} hybridization allows for:
Final Answer
The carbon atoms in C^2Cl^4 are sp^{2} hybridized.
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