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Step 1:I'll solve this problem step by step, focusing on drawing the Lewis dot structure for NOH^3.
Step 2:: Determine the central atom
- Nitrogen (N) will be the central atom in this molecule - It has the lowest electronegativity among the atoms present
Step 3:: Calculate the total number of valence electrons
- Total valence electrons: $$5 + 6 + (1 \times 3) = 14$$ electrons
- Nitrogen (N): 5 valence electrons - Oxygen (O): 6 valence electrons - Hydrogen (H): 1 valence electron × 3
Step 4:: Arrange electrons around the central nitrogen atom
- Connect the oxygen and three hydrogens to nitrogen - Distribute the remaining electrons to create a stable electron configuration - Ensure each atom follows the octet rule (except hydrogen, which needs 2 electrons)
Step 5:: Draw the Lewis dot structure
- Single bonds between N-O and N-H - Place remaining electrons as lone pairs - Final structure will show: * Nitrogen as the central atom * One single bond to oxygen * Three single bonds to hydrogens * Lone pairs on oxygen to complete its octet
Final Answer
The Lewis dot structure for NOH^3 will have nitrogen at the center, with single bonds to one oxygen and three hydrogens, with additional lone pairs on the oxygen to complete its electron configuration.
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