Answer
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Step 1:I'll solve this problem step by step, focusing on the Lewis structure for iodine.
Step 2:: Determine the number of valence electrons
\text{Valence electrons for I} = 7
- Iodine is in Group 17 (VIIA) of the periodic table - Iodine has 7 valence electrons
Step 3:: Consider the atomic structure
- Iodine is a halogen - It typically forms a diatomic molecule (I₂) - Each iodine atom will contribute its 7 valence electrons
Step 4:: Draw the Lewis structure
\begin{array}{c}
- Connect the two iodine atoms with a single covalent bond - Distribute the remaining electrons as lone pairs around each iodine atom - Ensure each atom has 8 electrons (octet rule) \text{Lewis Structure of I}_2 \ \ddot{I} - \ddot{I} \end{array} Key features: - Single bond between the two iodine atoms - 3 lone pairs on each iodine atom - Total of 14 valence electrons used
Final Answer
The Lewis structure for iodine (I₂) consists of a single bond between two iodine atoms, with 3 lone pairs of electrons on each iodine atom.
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