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Step 1:I'll solve this step-by-step using precise LaTeX formatting:
Step 2:: Identify the elements and their atomic masses
- Fe (Iron): $$m_{Fe} = 55.85 \mathrm{~g/mol}
- Br (Bromine): m_{Br} = 79.90 \mathrm{~g/mol}
Step 3:: Count the number of atoms in the compound
- FeBr^3 contains: * 1 Iron atom * 3 Bromine atoms
Step 4:: Calculate the molar mass by summing the atomic masses
\begin{align}
m_{FeBr_{3}} &= m_{Fe} + 3 \times m_{Br} \ &= 55.85 \mathrm{~g/mol} + 3 \times 79.90 \mathrm{~g/mol} \ &= 55.85 \mathrm{~g/mol} + 239.70 \mathrm{~g/mol} \ &= 295.55 \mathrm{~g/mol} \end{align}
Final Answer
The molar mass of FeBr^3 is 295.55 \mathrm{~g/mol}.
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