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Step 1:I'll solve this step-by-step using precise LaTeX formatting:
Step 2:: Identify the elements in AgNO₃
- Silver (Ag) - Nitrogen (N) - Oxygen (O)
Step 3:: Look up the atomic masses
- Oxygen (O): $$m_{O} = 16.00 \mathrm{~g/mol}
- Nitrogen (N): m_{N} = 14.01 \mathrm{~g/mol}
Step 4:: Calculate the number of atoms of each element
- Ag: 1 atom - N: 1 atom - O: 3 atoms
Step 5:: Calculate the total molar mass by summing the masses
\begin{align}
m_{\mathrm{AgNO_{3}}} &= m_{Ag} + m_{N} + (3 \times m_{O}) \ &= 107.87 + 14.01 + (3 \times 16.00) \ &= 107.87 + 14.01 + 48.00 \ &= 169.88 \mathrm{~g/mol} \end{align}
Final Answer
The molar mass of AgNO₃ is 169.88 \mathrm{~g/mol}.
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