QQuestionChemistry
QuestionChemistry
What is the molecular weight (molar mass) of Lead(III) Nitrate?
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Answer
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Step 1:I'll solve this step-by-step with precise LaTeX formatting:
Step 2:: Identify the chemical formula
The chemical formula for Lead(III) Nitrate is $$Pb(NO_{3})_{3}
Step 3:: Determine the atomic weights
- Oxygen (O): $$16.0 \frac{g}{mol}
- Nitrogen (N): 14.0 \frac{g}{mol}
Step 4:: Calculate the molecular weight
- Oxygen: $$3 \times 3 \times 16.0 \frac{g}{mol}
- Nitrogen: 3 \times 14.0 \frac{g}{mol}
Step 5:: Sum the atomic weights
207.2 + (3 \times 14.0) + (3 \times 3 \times 16.0) = 207.2 + 42.0 + 144.0
Final Answer
393.2 \frac{g}{mol}
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