QQuestionChemistry
QuestionChemistry
What is the ranking order of the degree of polarity of HF, HCl, HBr, and HI?
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Answer
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Step 1:: Recall the concept of polarity in chemistry.
Polarity refers to the separation of charges in a bond or a molecule. The degree of polarity depends on the electronegativity difference between the atoms forming the bond.
Step 2:: Review the electronegativities of the atoms involved.
The electronegativity values (on the Pauling scale) for hydrogen (H), fluorine (F), chlorine (Cl), bromine (Br), and iodine (I) are approximately 2.20, 4.0, 3.16, 2.96, and 2.66, respectively.
Step 3:: Calculate the electronegativity differences for each bond.
The degree of polarity increases as the electronegativity difference between the two atoms increases. - HF: |2.20 - 4.0| = 1.80 - HCl: |2.20 - 3.16| = 0.96 - HBr: |2.20 - 2.96| = 0.76 - HI: |2.20 - 2.66| = 0.46
Step 4:: Rank the bonds based on the electronegativity differences.
- HF: 1.80 - HCl: 0.96 - HBr: 0.76 - HI: 0.46
Final Answer
The ranking order of the degree of polarity for HF, HCl, HBr, and HI is HF > HCl > HBr > HI.
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