QQuestionChemistry
QuestionChemistry
What is the systematic name for V^3N^5?
If the charge on the metal remained the same and flourine was substituted for nitrogen, what would the formula for the compound be?
What is the difference in the total number of protons in the nitrogen and flourine compounds? Show all work
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Answer
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Step 1:I'll solve this step by step using the proper chemical nomenclature and LaTeX formatting:
Step 2:: Determine the systematic name for V^3N^5
- Solving for x: $$x = +5
- Vanadium (V) is a transition metal - Nitrogen (N) is a non-metal - The charge must be balanced - Vanadium has multiple possible oxidation states - In this compound, we need to determine the oxidation state of vanadium
Step 3:: Name the compound
- Vanadium is in the + 5 oxidation state - Systematic name: Vanadium(V) nitride
Step 4:: Substitute fluorine for nitrogen
- New formula: $$V_{3}F_{15}
- Fluorine has a - 1 charge
Step 5:: Calculate difference in total protons
204 - 104 = 100
- Vanadium atomic number: 23 - Nitrogen atomic number: 7 - Fluorine atomic number: 9 Protons in V^3N^5: Protons in V^3F^15: Difference in protons:
Final Answer
- Systematic name for V^3N^5: Vanadium(V) nitride - Substituted compound formula: V_{3}F_{15} - Difference in total protons: 100 protons
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