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QuestionChemistry

What is the total number of valence electrons in the Lewis structure of XeO^4?
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Answer

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Step 1:
I'll solve this step-by-step following the specified LaTeX formatting guidelines:

Step 2:
: Identify the elements

- Xe (Xenon) is in Group 18 (Noble Gases) - O (Oxygen) is in Group 16 (Chalcogens)

Step 3:
: Calculate valence electrons for Xenon

- Valence electrons for Xe = $$8$$ electrons
- Xenon is in Group 18

Step 4:
: Calculate valence electrons for Oxygen

- Total O valence electrons = $$6 \times 4 = 24$$ electrons
- Oxygen is in Group 16

Step 5:
: Sum total valence electrons

- $$= 32$$ valence electrons
- = 8 + 24

Final Answer

32 total valence electrons in the Lewis structure of XeO{4}