QQuestionChemistry
QuestionChemistry
Which element, Oxygen (O) or Fluorine (F), has a smaller atomic radius?
A. O, because the attraction between protons and valence electrons is weaker.
B. F, because the attraction between protons and valence electrons is stronger.
C. F, because the attraction between protons and valence electrons is weaker.
D. O, because the attraction between protons and valence electrons is stronger.
12 months agoReport content
Answer
Full Solution Locked
Sign in to view the complete step-by-step solution and unlock all study resources.
Step 1:I'll solve this problem step by step, focusing on atomic structure and periodic trends.
Step 2:: Understand Atomic Radius Trends
The atomic radius depends on several factors, primarily: - Number of protons in the nucleus - Number of electron shells - Effective nuclear charge - Electron-proton attraction
Step 3:: Examine Electron Configuration
- Oxygen (O): $$1s^{2} 2s^{2} 2p^{4}
- Fluorine (F): 1s^{2} 2s^{2} 2p^{5}
Step 4:: Compare Nuclear Charge
- Oxygen: 8 protons - Fluorine: 9 protons
Step 5:: Analyze Electron-Proton Attraction
As you move right across a period in the periodic table, nuclear charge increases while the number of electron shells remains constant. This leads to: - Stronger attraction between protons and electrons - Increased pulling of electrons closer to the nucleus - Smaller atomic radius
Step 6:: Determine Atomic Radius
Fluorine, being further right in period 2, will have: - Higher nuclear charge - Stronger electron-proton attraction - Smaller atomic radius
Final Answer
F, because the attraction between protons and valence electrons is stronger.
Need Help with Homework?
Stuck on a difficult problem? We've got you covered:
- Post your question or upload an image
- Get instant step-by-step solutions
- Learn from our AI and community of students