QQuestionChemistry
QuestionChemistry
"Which of the following molecules would violate the octet rule due to having odd numbers of electrons?
A. OH
B. NO₂⁺
C. NO
D. SO₂
E. ClO₂⁻
F. ClO"
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Answer
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Step 1:Let's solve this step by step:
Step 2:: Understand the Octet Rule
The octet rule states that atoms tend to combine in such a way that they each have eight electrons in their valence shell. Molecules with an odd number of total electrons will inherently violate this rule.
Step 3:: Determine Valence Electrons for Each Molecule
- Total: $$7 + 6 = 13$$ electrons (odd number)
I'll calculate the total number of valence electrons for each molecule: A. OH: - Oxygen: 6 valence electrons - Hydrogen: 1 valence electron B. NO₂⁺: - Nitrogen: 5 valence electrons - Oxygen: 6 × 2 = 12 valence electrons - Positive charge removes 1 electron C. NO: - Nitrogen: 5 valence electrons - Oxygen: 6 valence electrons D. SO₂: - Sulfur: 6 valence electrons - Oxygen: 6 × 2 = 12 valence electrons E. ClO₂⁻: - Chlorine: 7 valence electrons - Oxygen: 6 × 2 = 12 valence electrons - Negative charge adds 1 electron F. ClO: - Chlorine: 7 valence electrons - Oxygen: 6 valence electrons
Step 4:: Identify Molecules with Odd Electron Count
Molecules with an odd number of electrons violate the octet rule: - OH (7 electrons) - NO (11 electrons) - ClO (13 electrons)
Final Answer
A. OH C. NO F. ClO
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