QQuestionChemistry
QuestionChemistry
Which statements are correct when barium and oxygen react to form an ionic compound?
I. Each barium atom loses 2 electrons and forms a cation.
II. Oxygen atoms form oxide anions (O^2−).
III. The ions are present in a one-to-one ratio in the compound.
A. I and II only
B. II and III only
C. I and III only
D. I, II, and III
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Answer
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Step 1:Let's solve this step by step:
Step 2:: Understand the electron configuration of barium
Ba \rightarrow Ba^{2+} + 2e^{-}
- Barium (Ba) is in Group 2 (alkaline earth metals) - Its electron configuration is [Xe] 6s² - To achieve a stable electron configuration, barium will lose its 2 valence electrons - This forms a Ba²⁺ cation
Step 3:: Understand the electron configuration of oxygen
O + 2e^{-} \rightarrow O^{2-}
- Oxygen (O) is in Group 16 (chalcogens) - Its electron configuration is 1s² 2s² 2p⁴ - To achieve a stable electron configuration, oxygen needs to gain 2 electrons - This forms an O²⁻ anion
Step 4:: Determine the ionic compound formation
- Barium loses 2 electrons, forming Ba²⁺ - Oxygen gains 2 electrons, forming O²⁻ - To balance the charges, we need one Ba²⁺ and one O²⁻ - This means the ions are present in a one-to-one ratio
Step 5:: Evaluate each statement
- Statement I: Correct ✓ (barium loses 2 electrons) - Statement II: Correct ✓ (oxygen forms oxide anions) - Statement III: Correct ✓ (one-to-one ratio of Ba²⁺ to O²⁻)
Final Answer
I, II, and III are all correct statements about the ionic compound formed between barium and oxygen.
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