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Which structure is the Lewis structure for ammonia (NH3)?​ # $\circ$ A. $\mathrm{N}-\mathrm{H}-\mathrm{H}-\mathrm{H}$ $\circ$ B. $\quad \begin{array}{r}\mathrm{H} \\ \mid\end{array}$ \begin{array}{ll} \mathrm{H}-\mathrm{N}-\mathrm{H} \end{array} $\circ$ C. $\quad \begin{array}{r}\mathrm{H} \\ \mid\end{array}$ \begin{array}{ll} \mathrm{H}-\mathrm{N}-\mathrm{H} \end{array} $\circ$ D. $\mathrm{H}-\mathrm{N}-\mathrm{H}-\mathrm{H}$
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Step 1:
I'll solve this step by step using proper Lewis structure principles:

Step 2:
: Determine the central atom

- In ammonia ($$\mathrm{NH}_{3}$$), nitrogen (N) is the central atom
- Nitrogen is less electronegative and can form multiple bonds

Step 3:
: Calculate total valence electrons

- Total valence electrons: $$5 + (3 \times 1) = 8$$ electrons
- Nitrogen: 5 valence electrons - Hydrogen: 1 valence electron × 3 = 3 electrons

Step 4:
: Arrange electrons to satisfy octet rule

- Nitrogen wants 8 electrons - Hydrogen wants 2 electrons - Form single bonds between N and each H

Step 5:
: Draw Lewis structure

- Nitrogen in center - Three hydrogen atoms bonded to nitrogen - Correct structure looks like: \begin{array}{r} \mathrm{H} \ \mid \ \mathrm{H}-\mathrm{N}-\mathrm{H} \end{array}

Final Answer

Option B is the correct Lewis structure for ammonia (\mathrm{NH}_{3}).