QQuestionChemistry
QuestionChemistry
Write a Lewis structure for OF 2 , then answer the following questions about the Lewis structure:
How many valence electrons does this compound have?
How many bonded electrons does this compound have?
How many lone pairs of electrons does this compound have?
How many single bonds does this compound have?
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Answer
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Step 1:I'll solve this step by step, carefully following the LaTeX formatting guidelines:
Step 2:: Determine the total number of valence electrons
• Total valence electrons: $$6 + (7 \times 2) = 6 + 14 = 20$$ valence electrons
• Oxygen (O): 6 valence electrons • Fluorine (F): 7 valence electrons × 2
Step 3:: Draw the Lewis structure
• Place oxygen in the center • Attach two fluorine atoms to oxygen • Distribute remaining electrons as lone pairs • Lewis structure will look like: \begin{array}{c} F \ \downarrow \ O-F \end{array}
Step 4:: Count electrons in the Lewis structure
• Lone pair electrons: $$16$$ electrons
• Bonded electrons: 2 \times 1 = 2 single bonds Detailed electron accounting:
Final Answer
• Total valence electrons: 20 • Bonded electrons: 4 • Lone pair electrons: 16 • Single bonds: 2
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