CramX Logo

Q
QuestionChemistry

Write the following for KrF₄: Lewis structure Molecular geometry Hybridization Bond angle(s) Polarity
12 months agoReport content

Answer

Full Solution Locked

Sign in to view the complete step-by-step solution and unlock all study resources.

Step 1:
I'll solve this problem step by step for KrF₄, carefully following the LaTeX formatting guidelines:

Step 2:
: Determine the Central Atom and Valence Electrons

- Total valence electrons: $$8 + (4 \times 7) = 36$$ electrons
- Central atom is Kr (Krypton) - Kr is in Group 18 with 8 valence electrons - Each F atom contributes 7 valence electrons

Step 3:
: Lewis Structure

\begin{array}{c}
- Arrange F atoms symmetrically around Kr - Place single bonds between Kr and each F atom - Distribute remaining electrons as lone pairs - Lewis structure shows: F \ | \ Kr \ | \ F \end{array} - Four single Kr-F bonds - Multiple lone pairs on Kr and F atoms

Step 4:
: Molecular Geometry

- Central atom Kr has 4 bonds and 0 lone pairs - Molecular geometry is square planar - Follows AX₄ molecular geometry type

Step 5:
: Hybridization

- Kr uses $$d^{2}sp^{2}$$ hybridization
- Combines 2 d-orbitals and 2 p-orbitals - Creates four equivalent hybrid orbitals in square planar arrangement

Step 6:
: Bond Angles

- Bond angles are $$90°$$ between adjacent F atoms
- Square planar geometry - Symmetric arrangement around Kr

Step 7:
: Polarity

- Despite symmetric geometry - Kr-F bonds are polar due to electronegativity difference - Net molecular polarity is zero due to symmetrical arrangement

Final Answer

- Lewis Structure: Square planar KrF₄ with single Kr-F bonds - Molecular Geometry: Square planar - Hybridization: d^{2}sp^{2} - Bond Angles: 90° - Polarity: Non-polar molecule