QQuestionChemistry
QuestionChemistry
Write the full and abbreviated electron configurations for nickel.
How many core and valence electrons does it have?
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Answer
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Step 1:I'll solve this step by step using precise LaTeX formatting:
Step 2:: Determine Nickel's Atomic Number
- Nickel (Ni) is element 28 on the periodic table - This means nickel has 28 electrons to distribute in its electron configuration
Step 3:: Write the Full Electron Configuration
1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{8}
- Following the Aufbau principle, the electron configuration will be:
Step 4:: Write the Abbreviated Electron Configuration
[Ar] 4s^{2} 3d^{8}
- Use the noble gas [Ar] as the core configuration
Step 5:: Count Core and Valence Electrons
4s^{2} 3d^{8} = 10 \text{ valence electrons}
- Core electrons: All electrons in filled shells up to [Ar] - Valence electrons: Electrons in the outermost shell
Final Answer
- Full configuration: 1s^{2} 2s^{2} 2p^{6} 3s^{2} 3p^{6} 4s^{2} 3d^{8} - Abbreviated configuration: [Ar] 4s^{2} 3d^{8} - Core electrons: 18 - Valence electrons: 10
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