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Impact of Creative Writing Courses on Creativity Scores: A Comparative Analysis Using Dependent and Independent t Tests

A comparative analysis of creativity scores based on statistical testing methods.

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    Impact of Creative Writing Courses on Creativity Scores: A Comparative Analysis Using Dependent and Independent t Tests Analyze the impact of a creative writing course on creativity scores using dependent and independent t tests. Include exploratory data analysis, hypothesis formulation, and comparison of results. Present findings in APA style with relevant SPSS output. Word Count : 1,500 to 2,000 words

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    will submit one Word document and one SPSS data file for this week. You will create the Word document by cutting and pasting SPSS output into Word. Please read the instructions below to ensure you are pasting the correct material into your assignment document. Begin by downloading the following SPSS data sets:  Activity 6a.sav (found on the “additional resources” page)  Activity 6c.sav (found on the “additional resources” page) Part A. Dependent t test In this assignment, we are interested in finding out whether participation in a creative writing course results in increased scores of a creativity assessment. For this part of the assignment, you will be using the data file “Activity 6a.sav”. In this file, “Participant” is the numeric student identifier, “CreativityPre” contains creativity pre - test scores, and “CreativityPost” contains creativity post - test scores. A total of 40 students completed the pre - test, took the creativity course, and then took the post - test. 1. Exploratory Data Analysis/Hypotheses. 1. Perform exploratory data analysis on CreativityPre and CreativityPost. Using SPSS, calculate the mean and standard deviation of these two variables. 2. Construct an appropriate chart/graph that displays the relevant information for these two variables. 3. Write the null and alternative hypotheses used to test the question above (e.g., whether participation in the course affects writing scores). Output of Exploratory data analysis as performed in SPSS is shown below. Descriptive Statistics N Range Minimu m Maximu m Mean Std. Deviation Varianc e Creativity pre - test 40 30 26 56 40.15 8.304 68.951 Creativity post - test 40 39 20 59 43.35 9.598 92.131 Valid N (list wise) 40 From the above output I observe that mean and standard deviation of Pre - test is 40.15 and 8.304. While that mean and standard deviation of Post - test is 43.35 and 9.598. Histogram representing mean and standard deviation for pre - test is shown below. Clearly it follows Normal distribution.

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    Histogram representing mean and standard deviation for post - test is shown below. Clearly it follows Normal distribution.

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    Null Hypothesis, Ho: there is no significant difference between creativity Pre - test and creativity post - test. That is u1 – u2 = 0 Alternative Hypothesis: there is significant difference between creativity Pre - test and creativity post - test. That is u1 – u2 is not equal to 0 2. Comparison of Means 1. Perform a dependent t test to assess your hypotheses above (note that many versions of SPSS use the term “paired samples t test” rather than dependent t test; the test itself is the same. 2. Write one or two paragraphs that describe the dataset, gives your hypothesis, and presents the results of the dependent sample t test. Be sure that your writing conforms to APA style. Output obtained from SPSS by performing paired sample t test is shown below. Paired Samples Statistics Mean N Std. Deviation Std. Error Mean

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    Pair 1 Creativity pre - test 40.15 40 8.304 1.313 Creativity post - test 43.35 40 9.598 1.518 Paired Samples Correlations N Correlatio n Sig. Pair 1 Creativity pre - test & Creativity post - test 40 .650 .000 Paired Samples Test Paired Differences t df Sig. (2 - tailed) Mean Std. Deviation Std. Error Mean 95% Confidence Interval of the Difference Lower Upper Pair 1 Creativity pre - test - Creativity post - test - 3.200 7.576 1.198 - 5.623 - .777 - 2.671 39 .011 Here p - value = 0.011. Since, p - value is less than alpha (0.05), reject Ho at 5% level of significance and conclude there is significant difference between creativity Pre - test and creativity post - test. That is u1 – u2 is not equal to 0 Part B. Independent t test In this assignment, we will start with the data file used in Part A (“Activity 6a.sav”). Suppose, however, you [the researcher] encountered a small problem during data collection: after the post - tests were collected, you realized that the post - test form did not ask for the students’ identification number. As such, it will be impossible to match pre - test scores to post - test scores. Rather than simply give up, you start thinking about the data you do have, and try to determine whether you can salvage your project. In assessing the situation, you realize that you have 40 pre - test scores and 40 post - test scores, but no way to link them. While it will result in a weaker comparison, you determine that you are still able to compare pre - test vs. post - test scores; you will use a between - subjects design rather than a within - subjects design. 1. Create the data set. 1. Using the “Activity 6a.sav” file as a starting point, create a new dataset that you can use with the between subjects design. Hint: you will no longer need the variables Creative - Pre and Creative - Test. Instead, you have only one variable for

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