Geometric Calculations And Area/Perimeter Problem Solving

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Geometric Calculations and Area/Perimeter Problem SolvingThis is a right angle triangle so, area =12βˆ—π‘π‘Žπ‘ π‘’βˆ—β„Žπ‘’π‘–π‘”β„Žπ‘‘=12βˆ—3βˆ—4=3βˆ—2=6.In the same way, if we take 5 as base then x is the height.So, area =12βˆ—π‘π‘Žπ‘ π‘’βˆ—β„Žπ‘’π‘–π‘”β„Žπ‘‘=>6=12βˆ—5βˆ—π‘₯125=π‘₯So, answers are:Area = 6x =125.The area of shaded part =80βˆ—30+12βˆ—80βˆ—60+4βˆ—50=2400+2400+200

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=5000𝑓𝑑2So, we need just 1 bad of lawn food to cover the shaded region.Area of ABCD =π΅π‘Žπ‘ π‘’Γ—π»π‘’π‘–π‘”β„Žπ‘‘When we take base as AD then height will be CF.So,Area of ABCD =𝐴𝐷×𝐢𝐹=26Γ—12=312Now, if we take AB as base then height will be AE.Therefore,Area of ABCD =𝐴𝐡×𝐴𝐸=>312=π‘₯Γ—24=>π‘₯=31224=>π‘₯=13.Hence, answers are:Area = 312x = 13.

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We know, area of a rhombus =π‘π‘Žπ‘ π‘’βˆ—β„Žπ‘’π‘–π‘”β„Žπ‘‘=5π‘₯βˆ—4π‘₯=20π‘₯2So,20π‘₯2=720π‘₯2=36π‘₯=6So, base = 5x = 5*6 = 30Height = 4x = 4*6 = 24.So, base is 30 cm and height is 24 cm.Area of trapezoid =12(π‘ π‘’π‘šπ‘œπ‘“π‘π‘Žπ‘Ÿπ‘Žπ‘™π‘™π‘’π‘™π‘ π‘–π‘‘π‘’π‘ )βˆ—β„Žπ‘’π‘–π‘”β„Žπ‘‘=12(4+7)βˆ—4=11βˆ—2=22.So, area is22π‘π‘š2.

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Area of rhombus =12βˆ—π‘‘1βˆ—π‘‘2=12βˆ—6π‘₯βˆ—8π‘₯=24π‘₯2So,24π‘₯2=96π‘₯2=4π‘₯=2So, AC = 8x = 8*2 = 16 cm.BD = 6x = 6*2 = 12 cm.Area of a kite =12βˆ—π‘π‘Ÿπ‘œπ‘‘π‘’π‘π‘‘π‘œπ‘“π‘‘π‘–π‘Žπ‘”π‘œπ‘›π‘Žπ‘™π‘ =12βˆ—(4+4)βˆ—(5+3)=12βˆ—8βˆ—8Area =4βˆ—8=32π‘π‘š2.So, 32π‘π‘š2is the answer.
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