Precalculus: Concepts Through Functions, A Right Triangle Approach to Trigonometry, 4th Edition Test Bank

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TESTITEMFILE(DOWNLOAD ONLY)PRECALCULUS:CONCEPTSTHROUGHFUNCTIONS,ARIGHTTRIANGLEAPPROACH TOTRIGONOMETRYFOURTHEDITIONMICHAELSULLIVANChicago State UniversityMICHAELSULLIVANIIIJoliet Junior College

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Ch.0Foundations:APreludetoFunctions0.1TheDistanceandMidpointFormulas1UsetheDistanceFormulaMULTIPLECHOICE.Choosetheonealternativethatbestcompletesthestatementoranswersthequestion.Plotthepoint.1) (1,3)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6A)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6B)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6C)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6D)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6Page1

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2) (-5,1)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6A)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6B)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6C)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6D)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6Page2

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3) (1,-3)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6A)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6B)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6C)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6D)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6Page3

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4) (-4,-5)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6A)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6B)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6C)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6D)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6Page4

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5) (0,-1)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6A)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6B)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6C)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6D)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6Page5

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6) (4,0)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6A)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6B)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6C)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6D)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6Tellinwhichquadrantoronwhatcoordinateaxisthepointlies.7) (19,4)A) QuadrantIB) QuadrantIIC) QuadrantIIID) QuadrantIV8) (-14,17)A) QuadrantIIB) QuadrantIC) QuadrantIIID) QuadrantIV9) (-7,-13)A) QuadrantIIIB) QuadrantIC) QuadrantIID) QuadrantIV10) (10,-14)A) QuadrantIVB) QuadrantIC) QuadrantIID) QuadrantIIIPage6

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11) (0,3)A) y-axisB) x-axisC) QuadrantID) QuadrantII12) (-9,0)A) x-axisB) y-axisC) QuadrantID) QuadrantIIFindthedistanced(P1,P2)betweenthepointsP1 andP2.13)x-6-4-2246y642-2-4-6x-6-4-2246y642-2-4-6A) 25B)2C) 3D) 114)x-8-6-4-22468y8642-2-4-6-8x-8-6-4-22468y8642-2-4-6-8A)181B)19C) 90D) 1Page7

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15)x-8-6-4-22468y8642-2-4-6-8x-8-6-4-22468y8642-2-4-6-8A) 25B) 123C) 12D) 216)x-8-6-4-22468y8642-2-4-6-8x-8-6-4-22468y8642-2-4-6-8A) 35B) 273C) 27D) 317) P1=(-5,-5);P2=(-5,-3)A) 2B)2C) 3D) 118) P1=(-1,-2);P2=(-7,-10)A) 10B) 100C) 11D) 2019) P1=(0,-6);P2=(8,-6)A) 8B) 6C) 10D) 6420) P1=(0,0);P2=(-7,5)A)74B) 74C) 2D) 2321) P1=(5,1);P2=(-4,-3)A)97B)65C) 36D) 522) P1=(7,-7);P2=(5,-3)A) 25B) 123C) 12D) 6Page8

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23) P1=(-3,-2);P2=(7,-6)A) 229B) 8421C) 84D) 1424) P1=(0.4,0.9);P2=(-2.8,-1.3)Roundtothreedecimalplaces,ifnecessary.A) 3.883B) 27C) 12.28D) 3.983Decidewhetherornotthepointsaretheverticesofarighttriangle.25) (-9,9),(-2,9),(-2,15)A) YesB) No26) (-2,13),(0,17),(2,16)A) YesB) No27) (-3,9),(3,11),(2,6)A) NoB) Yes28) (8,1),(14,3),(20,-4)A) NoB) YesSolvetheproblem.29) Findallvaluesofksothatthegivenpointsare29unitsapart.(-5,5),(k,0)A)-3,-7B)-7C) 3,7D) 730) FindtheareaoftherighttriangleABCwithA=(-2,7),B=(7,-1),C=(3,9).A) 29squareunitsB) 58squareunitsC)582squareunitsD)292squareunits31) Findallthepointshavinganx-coordinateof9whosedistancefromthepoint(3,-2)is10.A) (9,6),(9,-10)B) (9,2),(9,-4)C) (9,-12),(9,8)D) (9,13),(9,-7)32) Amiddleschoolʹsbaseballplayingfieldisasquare,80 feetonaside.Howfarisitdirectlyfromhomeplatetosecondbase(thediagonalofthesquare)?Ifnecessary,roundtothenearestfoot.A) 113feetB) 114feetC) 112 feetD) 120 feet33) Amotorcycleandacarleaveanintersectionatthesametime.Themotorcycleheadsnorthatanaveragespeedof20milesperhour,whilethecarheadseastatanaveragespeedof48milesperhour.Findanexpressionfortheirdistanceapartinmilesattheendofthours.A) 52tmilesB) t68milesC) 52tmilesD) 2t13milesPage9

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34) FindthelengthofeachsideofthetriangledeterminedbythethreepointsP1,P2,andP3.Statewhetherthetriangleisanisoscelestriangle,arighttriangle,neitherofthese,orboth.P1=(-5,-4),P2=(-3,4),P3=(0,-1)A) d(P1,P2)=217;d(P2,P3)=34;d(P1,P3)=34bothB) d(P1,P2)=217;d(P2,P3)=34;d(P1,P3)=34isoscelestriangleC) d(P1,P2)=217;d(P2,P3)=34;d(P1,P3)=52righttriangleD) d(P1,P2)=217;d(P2,P3)=34;d(P1,P3)=52neither2UsetheMidpointFormulaMULTIPLECHOICE.Choosetheonealternativethatbestcompletesthestatementoranswersthequestion.FindthemidpointofthelinesegmentjoiningthepointsP1 andP2.1) P1=(9,8);P2=(1,4)A) (5,6)B) (10,12)C) (8,4)D) (6,5)2) P1=(-5,2);P2=(8,-7)A)32 ,-52B)-132 ,92C)-13,9D) 3,-53) P1=(7,1);P2=(-16,-16)A)-92 ,-152B)232 ,172C)-9,-15D) 9,154) P1=(-0.8,0.7);P2=(-1.2,-2.9)A) (-1,-1.1)B) (-1.1,-1)C) (-0.2,-1.8)D) (-1.8,-0.2)5) P1=(a,7);P2=(0,9)A)a2 ,8B) a,16C)-a2 ,2D) a,86) P1=(9x,7);P2=(10x,4)A)19x2,112B) 19x,11C) x,3D)11x2,192Solvetheproblem.7) If(-1,2)istheendpointofalinesegment,and(2,6)isitsmidpoint,findtheotherendpoint.A) (5,10)B) (5,-2)C) (-7,-6)D) (7,8)8) If(-1,-1)istheendpointofalinesegment,and(-4,-3)isitsmidpoint,findtheotherendpoint.A) (-7,-5)B) (-7,1)C) (5,3)D) (-5,-7)9) If(4,-5)istheendpointofalinesegment,and(9,-8)isitsmidpoint,findtheotherendpoint.A) (14,-11)B) (14,-2)C) (-6,1)D) (-2,5)Page10

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10) If(-3,1)istheendpointofalinesegment,and(-6,2)isitsmidpoint,findtheotherendpoint.A) (-9,3)B) (-9,0)C) (3,-1)D) (-1,-5)11) Themediansofatriangleintersectatapoint.Thedistancefromthevertextothepointisexactlytwo-thirdsofthedistancefromthevertextothemidpointoftheoppositeside.FindtheexactdistanceofthatpointfromthevertexA(3,4)ofatriangle,giventhattheothertwoverticesareat(0,0)and(8,0).A) 2173B)173C) 2D) 830.2GraphsofEquationsinTwoVariables;Intercepts;Symmetry1GraphEquationsbyPlottingPointsMULTIPLECHOICE.Choosetheonealternativethatbestcompletesthestatementoranswersthequestion.Determinewhetherthegivenpointisonthegraphoftheequation.1) Equation:y=x4-xPoint:(0,0)A) YesB) No2) Equation:x2-y2=16Point:( 22,22)A) NoB) YesPage11

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Graphtheequationbyplottingpoints.3) y=x+3x-10-5510y105-5-10x-10-5510y105-5-10A)x-10-5510y105-5-10x-10-5510y105-5-10B)x-10-5510y105-5-10x-10-5510y105-5-10C)x-10-5510y105-5-10x-10-5510y105-5-10D)x-10-5510y105-5-10x-10-5510y105-5-10Page12

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4) y=3x+9x-10-5510y105-5-10x-10-5510y105-5-10A)x-10-5510y105-5-10x-10-5510y105-5-10B)x-10-5510y105-5-10x-10-5510y105-5-10C)x-10-5510y105-5-10x-10-5510y105-5-10D)x-10-5510y105-5-10x-10-5510y105-5-10Page13

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5) y=-x2+9x-10-5510y105-5-10x-10-5510y105-5-10A)x-10-5510y105-5-10x-10-5510y105-5-10B)x-10-5510y105-5-10x-10-5510y105-5-10C)x-10-5510y105-5-10x-10-5510y105-5-10D)x-10-5510y105-5-10x-10-5510y105-5-10Page14
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